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2(4-x)=3(3x-2)
We move all terms to the left:
2(4-x)-(3(3x-2))=0
We add all the numbers together, and all the variables
2(-1x+4)-(3(3x-2))=0
We multiply parentheses
-2x-(3(3x-2))+8=0
We calculate terms in parentheses: -(3(3x-2)), so:We get rid of parentheses
3(3x-2)
We multiply parentheses
9x-6
Back to the equation:
-(9x-6)
-2x-9x+6+8=0
We add all the numbers together, and all the variables
-11x+14=0
We move all terms containing x to the left, all other terms to the right
-11x=-14
x=-14/-11
x=1+3/11
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