2(4-m)+4m=(-2+3m)

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Solution for 2(4-m)+4m=(-2+3m) equation: 



2(4-m)+4m=(-2+3m)

We move all terms to the left:

2(4-m)+4m-((-2+3m))=0

We add all the numbers together, and all the variables

2(-1m+4)+4m-((3m-2))=0

We add all the numbers together, and all the variables

4m+2(-1m+4)-((3m-2))=0

We multiply parentheses

4m-2m-((3m-2))+8=0



We calculate terms in parentheses: -((3m-2)), so:

(3m-2)

We get rid of parentheses

3m-2

Back to the equation:

-(3m-2)



We add all the numbers together, and all the variables

2m-(3m-2)+8=0

We get rid of parentheses

2m-3m+2+8=0

We add all the numbers together, and all the variables

-1m+10=0

We move all terms containing m to the left, all other terms to the right

-m=-10

m=-10/-1

m=+10

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