2(4-c+2c)=12

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Solution for 2(4-c+2c)=12 equation: 



2(4-c+2c)=12

We move all terms to the left:

2(4-c+2c)-(12)=0

We add all the numbers together, and all the variables

2(c+4)-12=0

We multiply parentheses

2c+8-12=0

We add all the numbers together, and all the variables

2c-4=0

We move all terms containing c to the left, all other terms to the right

2c=4

c=4/2

c=2

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