2(4-3x)+20=32-x

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Solution for 2(4-3x)+20=32-x equation: 



2(4-3x)+20=32-x

We move all terms to the left:

2(4-3x)+20-(32-x)=0

We add all the numbers together, and all the variables

2(-3x+4)-(-1x+32)+20=0

We multiply parentheses

-6x-(-1x+32)+8+20=0

We get rid of parentheses

-6x+1x-32+8+20=0

We add all the numbers together, and all the variables

-5x-4=0

We move all terms containing x to the left, all other terms to the right

-5x=4

x=4/-5

x=-4/5

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