2(4-2y)-3y=3-2(y+5)

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Solution for 2(4-2y)-3y=3-2(y+5) equation: 



2(4-2y)-3y=3-2(y+5)

We move all terms to the left:

2(4-2y)-3y-(3-2(y+5))=0

We add all the numbers together, and all the variables

2(-2y+4)-3y-(3-2(y+5))=0

We add all the numbers together, and all the variables

-3y+2(-2y+4)-(3-2(y+5))=0

We multiply parentheses

-3y-4y-(3-2(y+5))+8=0



We calculate terms in parentheses: -(3-2(y+5)), so:

3-2(y+5)

determiningTheFunctionDomain
-2(y+5)+3

We multiply parentheses

-2y-10+3

We add all the numbers together, and all the variables

-2y-7

Back to the equation:

-(-2y-7)



We add all the numbers together, and all the variables

-7y-(-2y-7)+8=0

We get rid of parentheses

-7y+2y+7+8=0

We add all the numbers together, and all the variables

-5y+15=0

We move all terms containing y to the left, all other terms to the right

-5y=-15

y=-15/-5

y=+3

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