2(4+3)+4f=6+6f

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Solution for 2(4+3)+4f=6+6f equation: 



2(4+3)+4f=6+6f

We move all terms to the left:

2(4+3)+4f-(6+6f)=0

We add all the numbers together, and all the variables

4f-(6f+6)+27=0

We get rid of parentheses

4f-6f-6+27=0

We add all the numbers together, and all the variables

-2f+21=0

We move all terms containing f to the left, all other terms to the right

-2f=-21

f=-21/-2

f=10+1/2

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