2(4+2r)=2(r+5)

Solution for 2(4+2r)=2(r+5) equation:

2(4+2r)=2(r+5)

We move all terms to the left:

2(4+2r)-(2(r+5))=0

We add all the numbers together, and all the variables

2(2r+4)-(2(r+5))=0

We multiply parentheses

4r-(2(r+5))+8=0


We calculate terms in parentheses: -(2(r+5)), so:

2(r+5)

We multiply parentheses

2r+10

Back to the equation:

-(2r+10)


We get rid of parentheses

4r-2r-10+8=0

We add all the numbers together, and all the variables

2r-2=0

We move all terms containing r to the left, all other terms to the right

2r=2

r=2/2

r=1