2(4+2n)=-(n-3)

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Solution for 2(4+2n)=-(n-3) equation: 



2(4+2n)=-(n-3)

We move all terms to the left:

2(4+2n)-(-(n-3))=0

We add all the numbers together, and all the variables

2(2n+4)-(-(n-3))=0

We multiply parentheses

4n-(-(n-3))+8=0



We calculate terms in parentheses: -(-(n-3)), so:

-(n-3)

We get rid of parentheses

-n+3

We add all the numbers together, and all the variables

-1n+3

Back to the equation:

-(-1n+3)



We get rid of parentheses

4n+1n-3+8=0

We add all the numbers together, and all the variables

5n+5=0

We move all terms containing n to the left, all other terms to the right

5n=-5

n=-5/5

n=-1

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