2(4+2i)+(2-3i)=0

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Solution for 2(4+2i)+(2-3i)=0 equation:


Simplifying
2(4 + 2i) + (2 + -3i) = 0
(4 * 2 + 2i * 2) + (2 + -3i) = 0
(8 + 4i) + (2 + -3i) = 0

Remove parenthesis around (2 + -3i)
8 + 4i + 2 + -3i = 0

Reorder the terms:
8 + 2 + 4i + -3i = 0

Combine like terms: 8 + 2 = 10
10 + 4i + -3i = 0

Combine like terms: 4i + -3i = 1i
10 + 1i = 0

Solving
10 + 1i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 1i = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 1i = 0 + -10
1i = 0 + -10

Combine like terms: 0 + -10 = -10
1i = -10

Divide each side by '1'.
i = -10

Simplifying
i = -10

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