2(4(-x)+1)=3(-x)+12

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Solution for 2(4(-x)+1)=3(-x)+12 equation: 



2(4(-x)+1)=3(-x)+12

We move all terms to the left:

2(4(-x)+1)-(3(-x)+12)=0

We add all the numbers together, and all the variables

2(4(-1x)+1)-(3(-1x)+12)=0



We calculate terms in parentheses: -(3(-1x)+12), so:

3(-1x)+12

We multiply parentheses

-3x+12

Back to the equation:

-(-3x+12)



We get rid of parentheses

2(4(-1x)+1)+3x-12=0

We add all the numbers together, and all the variables

3x+2(4(-1x)+1)-12=0

We move all terms containing x to the left, all other terms to the right

3x+2(4(-1x)+1)=12

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