2(3z-7)=22

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Solution for 2(3z-7)=22 equation: 



2(3z-7)=22

We move all terms to the left:

2(3z-7)-(22)=0

We multiply parentheses

6z-14-22=0

We add all the numbers together, and all the variables

6z-36=0

We move all terms containing z to the left, all other terms to the right

6z=36

z=36/6

z=6

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