2(3z-5)=38

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Solution for 2(3z-5)=38 equation: 



2(3z-5)=38

We move all terms to the left:

2(3z-5)-(38)=0

We multiply parentheses

6z-10-38=0

We add all the numbers together, and all the variables

6z-48=0

We move all terms containing z to the left, all other terms to the right

6z=48

z=48/6

z=8

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