2(3z-5)=11(z-15)

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Solution for 2(3z-5)=11(z-15) equation:


Simplifying
2(3z + -5) = 11(z + -15)

Reorder the terms:
2(-5 + 3z) = 11(z + -15)
(-5 * 2 + 3z * 2) = 11(z + -15)
(-10 + 6z) = 11(z + -15)

Reorder the terms:
-10 + 6z = 11(-15 + z)
-10 + 6z = (-15 * 11 + z * 11)
-10 + 6z = (-165 + 11z)

Solving
-10 + 6z = -165 + 11z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-11z' to each side of the equation.
-10 + 6z + -11z = -165 + 11z + -11z

Combine like terms: 6z + -11z = -5z
-10 + -5z = -165 + 11z + -11z

Combine like terms: 11z + -11z = 0
-10 + -5z = -165 + 0
-10 + -5z = -165

Add '10' to each side of the equation.
-10 + 10 + -5z = -165 + 10

Combine like terms: -10 + 10 = 0
0 + -5z = -165 + 10
-5z = -165 + 10

Combine like terms: -165 + 10 = -155
-5z = -155

Divide each side by '-5'.
z = 31

Simplifying
z = 31

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