2(3z-4)=7z+2

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Solution for 2(3z-4)=7z+2 equation:



2(3z-4)=7z+2
We move all terms to the left:
2(3z-4)-(7z+2)=0
We multiply parentheses
6z-(7z+2)-8=0
We get rid of parentheses
6z-7z-2-8=0
We add all the numbers together, and all the variables
-1z-10=0
We move all terms containing z to the left, all other terms to the right
-z=10
z=10/-1
z=-10

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