2(3z-1)=4(7-z)

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Solution for 2(3z-1)=4(7-z) equation: 



2(3z-1)=4(7-z)

We move all terms to the left:

2(3z-1)-(4(7-z))=0

We add all the numbers together, and all the variables

2(3z-1)-(4(-1z+7))=0

We multiply parentheses

6z-(4(-1z+7))-2=0



We calculate terms in parentheses: -(4(-1z+7)), so:

4(-1z+7)

We multiply parentheses

-4z+28

Back to the equation:

-(-4z+28)



We get rid of parentheses

6z+4z-28-2=0

We add all the numbers together, and all the variables

10z-30=0

We move all terms containing z to the left, all other terms to the right

10z=30

z=30/10

z=3

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