2(3z+1)-(4z-2)=22+4z

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Solution for 2(3z+1)-(4z-2)=22+4z equation:


Simplifying
2(3z + 1) + -1(4z + -2) = 22 + 4z

Reorder the terms:
2(1 + 3z) + -1(4z + -2) = 22 + 4z
(1 * 2 + 3z * 2) + -1(4z + -2) = 22 + 4z
(2 + 6z) + -1(4z + -2) = 22 + 4z

Reorder the terms:
2 + 6z + -1(-2 + 4z) = 22 + 4z
2 + 6z + (-2 * -1 + 4z * -1) = 22 + 4z
2 + 6z + (2 + -4z) = 22 + 4z

Reorder the terms:
2 + 2 + 6z + -4z = 22 + 4z

Combine like terms: 2 + 2 = 4
4 + 6z + -4z = 22 + 4z

Combine like terms: 6z + -4z = 2z
4 + 2z = 22 + 4z

Solving
4 + 2z = 22 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
4 + 2z + -4z = 22 + 4z + -4z

Combine like terms: 2z + -4z = -2z
4 + -2z = 22 + 4z + -4z

Combine like terms: 4z + -4z = 0
4 + -2z = 22 + 0
4 + -2z = 22

Add '-4' to each side of the equation.
4 + -4 + -2z = 22 + -4

Combine like terms: 4 + -4 = 0
0 + -2z = 22 + -4
-2z = 22 + -4

Combine like terms: 22 + -4 = 18
-2z = 18

Divide each side by '-2'.
z = -9

Simplifying
z = -9

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