2(3z)=6+2z

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Solution for 2(3z)=6+2z equation: 



2(3z)=6+2z

We move all terms to the left:

2(3z)-(6+2z)=0

We add all the numbers together, and all the variables

23z-(2z+6)=0

We get rid of parentheses

23z-2z-6=0

We add all the numbers together, and all the variables

21z-6=0

We move all terms containing z to the left, all other terms to the right

21z=6

z=6/21

z=2/7

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