2(3y-6)=41

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Solution for 2(3y-6)=41 equation: 



2(3y-6)=41

We move all terms to the left:

2(3y-6)-(41)=0

We multiply parentheses

6y-12-41=0

We add all the numbers together, and all the variables

6y-53=0

We move all terms containing y to the left, all other terms to the right

6y=53

y=53/6

y=8+5/6

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