2(3y-4)=42

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Solution for 2(3y-4)=42 equation: 



2(3y-4)=42

We move all terms to the left:

2(3y-4)-(42)=0

We multiply parentheses

6y-8-42=0

We add all the numbers together, and all the variables

6y-50=0

We move all terms containing y to the left, all other terms to the right

6y=50

y=50/6

y=8+1/3

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