2(3y-4)-4y=2(y-2)-7

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Solution for 2(3y-4)-4y=2(y-2)-7 equation:


Simplifying
2(3y + -4) + -4y = 2(y + -2) + -7

Reorder the terms:
2(-4 + 3y) + -4y = 2(y + -2) + -7
(-4 * 2 + 3y * 2) + -4y = 2(y + -2) + -7
(-8 + 6y) + -4y = 2(y + -2) + -7

Combine like terms: 6y + -4y = 2y
-8 + 2y = 2(y + -2) + -7

Reorder the terms:
-8 + 2y = 2(-2 + y) + -7
-8 + 2y = (-2 * 2 + y * 2) + -7
-8 + 2y = (-4 + 2y) + -7

Reorder the terms:
-8 + 2y = -4 + -7 + 2y

Combine like terms: -4 + -7 = -11
-8 + 2y = -11 + 2y

Add '-2y' to each side of the equation.
-8 + 2y + -2y = -11 + 2y + -2y

Combine like terms: 2y + -2y = 0
-8 + 0 = -11 + 2y + -2y
-8 = -11 + 2y + -2y

Combine like terms: 2y + -2y = 0
-8 = -11 + 0
-8 = -11

Solving
-8 = -11

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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