2(3y-15)=(4y+2)

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Solution for 2(3y-15)=(4y+2) equation: 



2(3y-15)=(4y+2)

We move all terms to the left:

2(3y-15)-((4y+2))=0

We multiply parentheses

6y-((4y+2))-30=0



We calculate terms in parentheses: -((4y+2)), so:

(4y+2)

We get rid of parentheses

4y+2

Back to the equation:

-(4y+2)



We get rid of parentheses

6y-4y-2-30=0

We add all the numbers together, and all the variables

2y-32=0

We move all terms containing y to the left, all other terms to the right

2y=32

y=32/2

y=16

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