2(3y-1)=7+(-22)

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Solution for 2(3y-1)=7+(-22) equation: 



2(3y-1)=7+(-22)

We move all terms to the left:

2(3y-1)-(7+(-22))=0

We add all the numbers together, and all the variables

2(3y-1)+15=0

We multiply parentheses

6y-2+15=0

We add all the numbers together, and all the variables

6y+13=0

We move all terms containing y to the left, all other terms to the right

6y=-13

y=-13/6

y=-2+1/6

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