2(3y-1)=2(y-1)

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Solution for 2(3y-1)=2(y-1) equation: 



2(3y-1)=2(y-1)

We move all terms to the left:

2(3y-1)-(2(y-1))=0

We multiply parentheses

6y-(2(y-1))-2=0



We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)



We get rid of parentheses

6y-2y+2-2=0

We add all the numbers together, and all the variables

4y=0

y=0/4

y=0

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