2(3y-1)+4y=5(2y+1)

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Solution for 2(3y-1)+4y=5(2y+1) equation: 



2(3y-1)+4y=5(2y+1)

We move all terms to the left:

2(3y-1)+4y-(5(2y+1))=0

We add all the numbers together, and all the variables

4y+2(3y-1)-(5(2y+1))=0

We multiply parentheses

4y+6y-(5(2y+1))-2=0



We calculate terms in parentheses: -(5(2y+1)), so:

5(2y+1)

We multiply parentheses

10y+5

Back to the equation:

-(10y+5)



We add all the numbers together, and all the variables

10y-(10y+5)-2=0

We get rid of parentheses

10y-10y-5-2=0

We add all the numbers together, and all the variables

-7!=0

There is no solution for this equation

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