2(3y-1)+2(y-4)=13

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Solution for 2(3y-1)+2(y-4)=13 equation:


Simplifying
2(3y + -1) + 2(y + -4) = 13

Reorder the terms:
2(-1 + 3y) + 2(y + -4) = 13
(-1 * 2 + 3y * 2) + 2(y + -4) = 13
(-2 + 6y) + 2(y + -4) = 13

Reorder the terms:
-2 + 6y + 2(-4 + y) = 13
-2 + 6y + (-4 * 2 + y * 2) = 13
-2 + 6y + (-8 + 2y) = 13

Reorder the terms:
-2 + -8 + 6y + 2y = 13

Combine like terms: -2 + -8 = -10
-10 + 6y + 2y = 13

Combine like terms: 6y + 2y = 8y
-10 + 8y = 13

Solving
-10 + 8y = 13

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 8y = 13 + 10

Combine like terms: -10 + 10 = 0
0 + 8y = 13 + 10
8y = 13 + 10

Combine like terms: 13 + 10 = 23
8y = 23

Divide each side by '8'.
y = 2.875

Simplifying
y = 2.875

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