2(3y+4)=3(4y+1)

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Solution for 2(3y+4)=3(4y+1) equation: 



2(3y+4)=3(4y+1)

We move all terms to the left:

2(3y+4)-(3(4y+1))=0

We multiply parentheses

6y-(3(4y+1))+8=0



We calculate terms in parentheses: -(3(4y+1)), so:

3(4y+1)

We multiply parentheses

12y+3

Back to the equation:

-(12y+3)



We get rid of parentheses

6y-12y-3+8=0

We add all the numbers together, and all the variables

-6y+5=0

We move all terms containing y to the left, all other terms to the right

-6y=-5

y=-5/-6

y=5/6

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