2(3y+4)-10=3(2y-3)+7

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Solution for 2(3y+4)-10=3(2y-3)+7 equation:


Simplifying
2(3y + 4) + -10 = 3(2y + -3) + 7

Reorder the terms:
2(4 + 3y) + -10 = 3(2y + -3) + 7
(4 * 2 + 3y * 2) + -10 = 3(2y + -3) + 7
(8 + 6y) + -10 = 3(2y + -3) + 7

Reorder the terms:
8 + -10 + 6y = 3(2y + -3) + 7

Combine like terms: 8 + -10 = -2
-2 + 6y = 3(2y + -3) + 7

Reorder the terms:
-2 + 6y = 3(-3 + 2y) + 7
-2 + 6y = (-3 * 3 + 2y * 3) + 7
-2 + 6y = (-9 + 6y) + 7

Reorder the terms:
-2 + 6y = -9 + 7 + 6y

Combine like terms: -9 + 7 = -2
-2 + 6y = -2 + 6y

Add '2' to each side of the equation.
-2 + 2 + 6y = -2 + 2 + 6y

Combine like terms: -2 + 2 = 0
0 + 6y = -2 + 2 + 6y
6y = -2 + 2 + 6y

Combine like terms: -2 + 2 = 0
6y = 0 + 6y
6y = 6y

Add '-6y' to each side of the equation.
6y + -6y = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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