2(3y+4)+2(4y+3)=8(2y+1)

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Solution for 2(3y+4)+2(4y+3)=8(2y+1) equation: 



2(3y+4)+2(4y+3)=8(2y+1)

We move all terms to the left:

2(3y+4)+2(4y+3)-(8(2y+1))=0

We multiply parentheses

6y+8y-(8(2y+1))+8+6=0



We calculate terms in parentheses: -(8(2y+1)), so:

8(2y+1)

We multiply parentheses

16y+8

Back to the equation:

-(16y+8)



We add all the numbers together, and all the variables

14y-(16y+8)+14=0

We get rid of parentheses

14y-16y-8+14=0

We add all the numbers together, and all the variables

-2y+6=0

We move all terms containing y to the left, all other terms to the right

-2y=-6

y=-6/-2

y=+3

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