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2(3y+2)=5(y+2)-4
We move all terms to the left:
2(3y+2)-(5(y+2)-4)=0
We multiply parentheses
6y-(5(y+2)-4)+4=0
We calculate terms in parentheses: -(5(y+2)-4), so:We get rid of parentheses
5(y+2)-4
We multiply parentheses
5y+10-4
We add all the numbers together, and all the variables
5y+6
Back to the equation:
-(5y+6)
6y-5y-6+4=0
We add all the numbers together, and all the variables
y-2=0
We move all terms containing y to the left, all other terms to the right
y=2
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