2(3y+10)=2(3y+10)=38

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Solution for 2(3y+10)=2(3y+10)=38 equation: 



2(3y+10)=2(3y+10)=38

We move all terms to the left:

2(3y+10)-(2(3y+10))=0

We multiply parentheses

6y-(2(3y+10))+20=0



We calculate terms in parentheses: -(2(3y+10)), so:

2(3y+10)

We multiply parentheses

6y+20

Back to the equation:

-(6y+20)



We get rid of parentheses

6y-6y-20+20=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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