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2(3y+1/3)=3(5y+1/3)
We move all terms to the left:
2(3y+1/3)-(3(5y+1/3))=0
We add all the numbers together, and all the variables
2(+3y+1/3)-(3(+5y+1/3))=0
We multiply parentheses
6y-(3(+5y+1/3))+1/3*2=0
We calculate fractions
6y+(-(3(+5y+1*3*2)/()+()/()=0
We calculate terms in parentheses: +(-(3(+5y+1*3*2)/()+()/(), so:
-(3(+5y+1*3*2)/()+()/(
We can not solve this equation
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