2(3y+1)(2y-1)/3(2y-1)(3y)

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Solution for 2(3y+1)(2y-1)/3(2y-1)(3y) equation: 


y in (-oo:+oo)

3*y*((2*(3*y+1)*(2*y-1))/3)*(2*y-1) = 0

(2*3*y*(3*y+1)*(2*y-1)^2)/3 = 0

( 2*y-1 )

2*y-1 = 0 // + 1

2*y = 1 // : 2

y = 1/2

( 3*y+1 )

3*y+1 = 0 // - 1

3*y = -1 // : 3

y = -1/3

( 3*y )

3*y = 0 // : 3

y = 0

y in { 1/2, 1/2, -1/3, 0 }

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