2(3x2)=20

Solution for 2(3x2)=20 equation:

2(3x^2)=20

We move all terms to the left:

2(3x^2)-(20)=0

a = 23; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·23·(-20)
Δ = 1840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1840}=\sqrt{16*115}=\sqrt{16}*\sqrt{115}=4\sqrt{115}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{115}}{2*23}=\frac{0-4\sqrt{115}}{46}
=-\frac{4\sqrt{115}}{46}
=-\frac{2\sqrt{115}}{23}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{115}}{2*23}=\frac{0+4\sqrt{115}}{46}
=\frac{4\sqrt{115}}{46}
=\frac{2\sqrt{115}}{23}
$