2(3x-8)-5+7x=8-(2-x)+8x

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Solution for 2(3x-8)-5+7x=8-(2-x)+8x equation: 



2(3x-8)-5+7x=8-(2-x)+8x

We move all terms to the left:

2(3x-8)-5+7x-(8-(2-x)+8x)=0

We add all the numbers together, and all the variables

2(3x-8)+7x-(8-(-1x+2)+8x)-5=0

We add all the numbers together, and all the variables

7x+2(3x-8)-(8-(-1x+2)+8x)-5=0

We multiply parentheses

7x+6x-(8-(-1x+2)+8x)-16-5=0



We calculate terms in parentheses: -(8-(-1x+2)+8x), so:

8-(-1x+2)+8x

determiningTheFunctionDomain
-(-1x+2)+8x+8

We add all the numbers together, and all the variables

8x-(-1x+2)+8

We get rid of parentheses

8x+1x-2+8

We add all the numbers together, and all the variables

9x+6

Back to the equation:

-(9x+6)



We add all the numbers together, and all the variables

13x-(9x+6)-21=0

We get rid of parentheses

13x-9x-6-21=0

We add all the numbers together, and all the variables

4x-27=0

We move all terms containing x to the left, all other terms to the right

4x=27

x=27/4

x=6+3/4

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