2(3x-7)+6(x-2)=-3(5-5x)+5x-1

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Solution for 2(3x-7)+6(x-2)=-3(5-5x)+5x-1 equation: 



2(3x-7)+6(x-2)=-3(5-5x)+5x-1

We move all terms to the left:

2(3x-7)+6(x-2)-(-3(5-5x)+5x-1)=0

We add all the numbers together, and all the variables

2(3x-7)+6(x-2)-(-3(-5x+5)+5x-1)=0

We multiply parentheses

6x+6x-(-3(-5x+5)+5x-1)-14-12=0



We calculate terms in parentheses: -(-3(-5x+5)+5x-1), so:

-3(-5x+5)+5x-1

We add all the numbers together, and all the variables

5x-3(-5x+5)-1

We multiply parentheses

5x+15x-15-1

We add all the numbers together, and all the variables

20x-16

Back to the equation:

-(20x-16)



We add all the numbers together, and all the variables

12x-(20x-16)-26=0

We get rid of parentheses

12x-20x+16-26=0

We add all the numbers together, and all the variables

-8x-10=0

We move all terms containing x to the left, all other terms to the right

-8x=10

x=10/-8

x=-1+1/4

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