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2(3x-5)=5-2(1-x)
We move all terms to the left:
2(3x-5)-(5-2(1-x))=0
We add all the numbers together, and all the variables
2(3x-5)-(5-2(-1x+1))=0
We multiply parentheses
6x-(5-2(-1x+1))-10=0
We calculate terms in parentheses: -(5-2(-1x+1)), so:We get rid of parentheses
5-2(-1x+1)
determiningTheFunctionDomain -2(-1x+1)+5
We multiply parentheses
2x-2+5
We add all the numbers together, and all the variables
2x+3
Back to the equation:
-(2x+3)
6x-2x-3-10=0
We add all the numbers together, and all the variables
4x-13=0
We move all terms containing x to the left, all other terms to the right
4x=13
x=13/4
x=3+1/4
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