2(3x-5)=4(x+1)+4(1-x)

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Solution for 2(3x-5)=4(x+1)+4(1-x) equation: 



2(3x-5)=4(x+1)+4(1-x)

We move all terms to the left:

2(3x-5)-(4(x+1)+4(1-x))=0

We add all the numbers together, and all the variables

2(3x-5)-(4(x+1)+4(-1x+1))=0

We multiply parentheses

6x-(4(x+1)+4(-1x+1))-10=0



We calculate terms in parentheses: -(4(x+1)+4(-1x+1)), so:

4(x+1)+4(-1x+1)

We multiply parentheses

4x-4x+4+4

We add all the numbers together, and all the variables

8

Back to the equation:

-(8)



We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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