2(3x-5)=-2(2x+20)

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Solution for 2(3x-5)=-2(2x+20) equation: 



2(3x-5)=-2(2x+20)

We move all terms to the left:

2(3x-5)-(-2(2x+20))=0

We multiply parentheses

6x-(-2(2x+20))-10=0



We calculate terms in parentheses: -(-2(2x+20)), so:

-2(2x+20)

We multiply parentheses

-4x-40

Back to the equation:

-(-4x-40)



We get rid of parentheses

6x+4x+40-10=0

We add all the numbers together, and all the variables

10x+30=0

We move all terms containing x to the left, all other terms to the right

10x=-30

x=-30/10

x=-3

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