2(3x-5)-4x=2-(x-6)+8

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Solution for 2(3x-5)-4x=2-(x-6)+8 equation: 



2(3x-5)-4x=2-(x-6)+8

We move all terms to the left:

2(3x-5)-4x-(2-(x-6)+8)=0

We add all the numbers together, and all the variables

-4x+2(3x-5)-(2-(x-6)+8)=0

We multiply parentheses

-4x+6x-(2-(x-6)+8)-10=0



We calculate terms in parentheses: -(2-(x-6)+8), so:

2-(x-6)+8

determiningTheFunctionDomain
-(x-6)+2+8

We add all the numbers together, and all the variables

-(x-6)+10

We get rid of parentheses

-x+6+10

We add all the numbers together, and all the variables

-1x+16

Back to the equation:

-(-1x+16)



We add all the numbers together, and all the variables

2x-(-1x+16)-10=0

We get rid of parentheses

2x+1x-16-10=0

We add all the numbers together, and all the variables

3x-26=0

We move all terms containing x to the left, all other terms to the right

3x=26

x=26/3

x=8+2/3

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