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2(3x-5)+3=4x-(2x+3)+2
We move all terms to the left:
2(3x-5)+3-(4x-(2x+3)+2)=0
We multiply parentheses
6x-(4x-(2x+3)+2)-10+3=0
We calculate terms in parentheses: -(4x-(2x+3)+2), so:We add all the numbers together, and all the variables
4x-(2x+3)+2
We get rid of parentheses
4x-2x-3+2
We add all the numbers together, and all the variables
2x-1
Back to the equation:
-(2x-1)
6x-(2x-1)-7=0
We get rid of parentheses
6x-2x+1-7=0
We add all the numbers together, and all the variables
4x-6=0
We move all terms containing x to the left, all other terms to the right
4x=6
x=6/4
x=1+1/2
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