2(3x-4)-(x-8)=3(4x+2)-7x-1

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Solution for 2(3x-4)-(x-8)=3(4x+2)-7x-1 equation: 



2(3x-4)-(x-8)=3(4x+2)-7x-1

We move all terms to the left:

2(3x-4)-(x-8)-(3(4x+2)-7x-1)=0

We multiply parentheses

6x-(x-8)-(3(4x+2)-7x-1)-8=0

We get rid of parentheses

6x-x-(3(4x+2)-7x-1)+8-8=0



We calculate terms in parentheses: -(3(4x+2)-7x-1), so:

3(4x+2)-7x-1

We add all the numbers together, and all the variables

-7x+3(4x+2)-1

We multiply parentheses

-7x+12x+6-1

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

5x-(5x+5)=0

We get rid of parentheses

5x-5x-5=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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