2(3x-4)+6(x-5)=-3(5-5x)+5x-13

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Solution for 2(3x-4)+6(x-5)=-3(5-5x)+5x-13 equation: 



2(3x-4)+6(x-5)=-3(5-5x)+5x-13

We move all terms to the left:

2(3x-4)+6(x-5)-(-3(5-5x)+5x-13)=0

We add all the numbers together, and all the variables

2(3x-4)+6(x-5)-(-3(-5x+5)+5x-13)=0

We multiply parentheses

6x+6x-(-3(-5x+5)+5x-13)-8-30=0



We calculate terms in parentheses: -(-3(-5x+5)+5x-13), so:

-3(-5x+5)+5x-13

We add all the numbers together, and all the variables

5x-3(-5x+5)-13

We multiply parentheses

5x+15x-15-13

We add all the numbers together, and all the variables

20x-28

Back to the equation:

-(20x-28)



We add all the numbers together, and all the variables

12x-(20x-28)-38=0

We get rid of parentheses

12x-20x+28-38=0

We add all the numbers together, and all the variables

-8x-10=0

We move all terms containing x to the left, all other terms to the right

-8x=10

x=10/-8

x=-1+1/4

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