2(3x-4)+5(6x-7)-3x=9(x+10)+11(x+12)+8

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Solution for 2(3x-4)+5(6x-7)-3x=9(x+10)+11(x+12)+8 equation: 



2(3x-4)+5(6x-7)-3x=9(x+10)+11(x+12)+8

We move all terms to the left:

2(3x-4)+5(6x-7)-3x-(9(x+10)+11(x+12)+8)=0

We add all the numbers together, and all the variables

-3x+2(3x-4)+5(6x-7)-(9(x+10)+11(x+12)+8)=0

We multiply parentheses

-3x+6x+30x-(9(x+10)+11(x+12)+8)-8-35=0



We calculate terms in parentheses: -(9(x+10)+11(x+12)+8), so:

9(x+10)+11(x+12)+8

We multiply parentheses

9x+11x+90+132+8

We add all the numbers together, and all the variables

20x+230

Back to the equation:

-(20x+230)



We add all the numbers together, and all the variables

33x-(20x+230)-43=0

We get rid of parentheses

33x-20x-230-43=0

We add all the numbers together, and all the variables

13x-273=0

We move all terms containing x to the left, all other terms to the right

13x=273

x=273/13

x=21

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