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2(3x-4)+1=5(x-2)-3
We move all terms to the left:
2(3x-4)+1-(5(x-2)-3)=0
We multiply parentheses
6x-(5(x-2)-3)-8+1=0
We calculate terms in parentheses: -(5(x-2)-3), so:We add all the numbers together, and all the variables
5(x-2)-3
We multiply parentheses
5x-10-3
We add all the numbers together, and all the variables
5x-13
Back to the equation:
-(5x-13)
6x-(5x-13)-7=0
We get rid of parentheses
6x-5x+13-7=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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