2(3x-20)+2(4x+10)=2(3x+30)

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Solution for 2(3x-20)+2(4x+10)=2(3x+30) equation: 



2(3x-20)+2(4x+10)=2(3x+30)

We move all terms to the left:

2(3x-20)+2(4x+10)-(2(3x+30))=0

We multiply parentheses

6x+8x-(2(3x+30))-40+20=0



We calculate terms in parentheses: -(2(3x+30)), so:

2(3x+30)

We multiply parentheses

6x+60

Back to the equation:

-(6x+60)



We add all the numbers together, and all the variables

14x-(6x+60)-20=0

We get rid of parentheses

14x-6x-60-20=0

We add all the numbers together, and all the variables

8x-80=0

We move all terms containing x to the left, all other terms to the right

8x=80

x=80/8

x=10

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