2(3x-2)=6(2x-5)

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Solution for 2(3x-2)=6(2x-5) equation: 



2(3x-2)=6(2x-5)

We move all terms to the left:

2(3x-2)-(6(2x-5))=0

We multiply parentheses

6x-(6(2x-5))-4=0



We calculate terms in parentheses: -(6(2x-5)), so:

6(2x-5)

We multiply parentheses

12x-30

Back to the equation:

-(12x-30)



We get rid of parentheses

6x-12x+30-4=0

We add all the numbers together, and all the variables

-6x+26=0

We move all terms containing x to the left, all other terms to the right

-6x=-26

x=-26/-6

x=4+1/3

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