2(3x-2)=38-x

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Solution for 2(3x-2)=38-x equation: 



2(3x-2)=38-x

We move all terms to the left:

2(3x-2)-(38-x)=0

We add all the numbers together, and all the variables

2(3x-2)-(-1x+38)=0

We multiply parentheses

6x-(-1x+38)-4=0

We get rid of parentheses

6x+1x-38-4=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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