2(3x-2)=-5(x+1)

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Solution for 2(3x-2)=-5(x+1) equation: 



2(3x-2)=-5(x+1)

We move all terms to the left:

2(3x-2)-(-5(x+1))=0

We multiply parentheses

6x-(-5(x+1))-4=0



We calculate terms in parentheses: -(-5(x+1)), so:

-5(x+1)

We multiply parentheses

-5x-5

Back to the equation:

-(-5x-5)



We get rid of parentheses

6x+5x+5-4=0

We add all the numbers together, and all the variables

11x+1=0

We move all terms containing x to the left, all other terms to the right

11x=-1

x=-1/11

x=-1/11

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