2(3x-2)=-3(x-2)+4x

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Solution for 2(3x-2)=-3(x-2)+4x equation: 



2(3x-2)=-3(x-2)+4x

We move all terms to the left:

2(3x-2)-(-3(x-2)+4x)=0

We multiply parentheses

6x-(-3(x-2)+4x)-4=0



We calculate terms in parentheses: -(-3(x-2)+4x), so:

-3(x-2)+4x

We add all the numbers together, and all the variables

4x-3(x-2)

We multiply parentheses

4x-3x+6

We add all the numbers together, and all the variables

x+6

Back to the equation:

-(x+6)



We get rid of parentheses

6x-x-6-4=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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