2(3x-2)-3(4-5x)=7(1-2x)+12

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Solution for 2(3x-2)-3(4-5x)=7(1-2x)+12 equation: 



2(3x-2)-3(4-5x)=7(1-2x)+12

We move all terms to the left:

2(3x-2)-3(4-5x)-(7(1-2x)+12)=0

We add all the numbers together, and all the variables

2(3x-2)-3(-5x+4)-(7(-2x+1)+12)=0

We multiply parentheses

6x+15x-(7(-2x+1)+12)-4-12=0



We calculate terms in parentheses: -(7(-2x+1)+12), so:

7(-2x+1)+12

We multiply parentheses

-14x+7+12

We add all the numbers together, and all the variables

-14x+19

Back to the equation:

-(-14x+19)



We add all the numbers together, and all the variables

21x-(-14x+19)-16=0

We get rid of parentheses

21x+14x-19-16=0

We add all the numbers together, and all the variables

35x-35=0

We move all terms containing x to the left, all other terms to the right

35x=35

x=35/35

x=1

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